/*

All interval problem in Picat.

CSPLib problem number 7
http://www.csplib.org/Problems/prob007
"""
Given the twelve standard pitch-classes (c, c , d, ...), represented by
numbers 0,1,...,11, find a series in which each pitch-class occurs exactly
once and in which the musical intervals between neighbouring notes cover
the full set of intervals from the minor second (1 semitone) to the major
seventh (11 semitones). That is, for each of the intervals, there is a
pair of neigbhouring pitch-classes in the series, between which this
interval appears. The problem of finding such a series can be easily
formulated as an instance of a more general arithmetic problem on Z_n,
the set of integer residues modulo n. Given n in N, find a vector
s = (s_1, ..., s_n), such that (i) s is a permutation of
Z_n = {0,1,...,n-1}; and (ii) the interval vector
v = (|s_2-s_1|, |s_3-s_2|, ... |s_n-s_{n-1}|) is a permutation of
Z_n-{0} = {1,2,...,n-1}. A vector v satisfying these conditions is
called an all-interval series of size n; the problem of finding such
a series is the all-interval series problem of size n. We may also be
interested in finding all possible series of a given size.
"""

Model created by Hakan Kjellerstrand, hakank@gmail.com

*/

% Licenced under CC-BY-4.0 : http://creativecommons.org/licenses/by/4.0/

import cp.

main => time2(go).

go =>
N = 12,
L = findall(X,all_interval(N,X,[])),
Len = length(L),
writef("Total: %d\n", Len).

% Just the first solution
go2 =>
foreach(N in 2..220)
writeln(n=N),
time2(\$all_interval(N,_X,[ff,split]))
end,
nl.

go3 =>
all_interval(2000,X,[ff,split]),
writeln(X),
nl.

all_interval(N,X,Label) =>

X = new_list(N),
X :: 1..N,

N1 = N-1,
Diffs = new_list(N1),
Diffs :: 1..N1,

SumDistinct = ((N+1)*N) // 2,

all_different(X),
all_different(Diffs),

foreach(K in 1..N1)
Diffs[K] #= abs(X[K+1] - X[K])
end,

% symmetry breaking
X[1] #< X[N1],
Diffs[1] #< Diffs[2],

Vars = X ++ Diffs,

% symmetry breaking for one solutions
% increasing(Diffs),

%
% This first solution is found very fast using [ff,split],
% then the Diffs is the sequence 1..N-1.
% For getting all solution, the default labeling is better.
%
% solve([ff,down], Vars),
% solve([ff,split], Vars),
solve(Label, Vars),
% solve(Vars),
writef("x: %w  diffs: %w  [sum: %d]\n", X, Diffs, SumDistinct).

increasing(List) =>
foreach(I in 2..List.length) List[I-1] #=< List[I] end.