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/*
Social golfer problem in Picat.
CSPLib problem 10:
http://www.csplib.org/Problems/prob010/index.html
"""
The coordinator of a local golf club has come to you with the following
problem. In her club, there are 32 social golfers, each of whom play golf
once a week, and always in groups of 4. She would like you to come up
with a schedule of play for these golfers, to last as many weeks as
possible, such that no golfer plays in the same group as any other golfer
on more than one occasion.
Possible variants of the above problem include: finding a 10-week schedule
with ``maximum socialisation''; that is, as few repeated pairs as possible
(this has the same solutions as the original problem if it is possible
to have no repeated pairs), and finding a schedule of minimum length
such that each golfer plays with every other golfer at least once
(``full socialisation'').
The problem can easily be generalized to that of scheduling m groups of
n golfers over p weeks, such that no golfer plays in the same group as any
other golfer twice (i.e. maximum socialisation is achieved).
"""
This model is a translation of the OPL code from
http://www.dis.uniroma1.it/~tmancini/index.php?currItem=research.publications.webappendices.csplib2x.problemDetails&problemid=010
Model created by Hakan Kjellerstrand, hakank@gmail.com
See also my Picat page: http://www.hakank.org/picat/
*/
% Licenced under CC-BY-4.0 : http://creativecommons.org/licenses/by/4.0/
import cp.
main => go.
go =>
Weeks = 5,
Groups = 7,
GroupSize = 3,
Golfers = Groups * GroupSize,
Golfer = 1..Golfers,
Week = 1..Weeks,
Group = 1..Groups,
% decision variables
Assign = new_array(Golfers,Weeks),
Assign :: 1..Groups,
% C1: Each group has exactly groupSize players
foreach(Gr in Group, W in Week)
sum([(Assign[G,W] #= Gr) : G in Golfer]) #= GroupSize
end,
% C2: Each pair of players only meets at most once
foreach(G1 in Golfer,G2 in Golfer, W1 in Week, W2 in Week)
if G1 != G2, W1 != W2 then
(Assign[G1,W1] #= Assign[G2,W1]) +
(Assign[G1,W2] #= Assign[G2,W2]) #=< 1
end
end,
% SBSA: Symmetry-breaking by selective assignment
% On the first week, the first groupSize golfers play in group 1, the
% second groupSize golfers play in group 2, etc. On the second week,
% golfer 1 plays in group 1, golfer 2 plays in group 2, etc.
foreach(G in Golfer) Assign[G,1] #= ((G-1) // GroupSize) + 1 end,
foreach(G in Golfer)
if G =< GroupSize then Assign[G,2] #= G end
end,
solve([ff], Assign),
foreach(Row in Assign) writeln(Row) end,
nl.